10-2x^2=-5

Solution for 10-2x^2=-5 equation:

10-2x^2=-5

We move all terms to the left:

10-2x^2-(-5)=0

We add all the numbers together, and all the variables

-2x^2+15=0

a = -2; b = 0; c = +15;
Δ = b2-4ac
Δ = 02-4·(-2)·15
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{30}}{2*-2}=\frac{0-2\sqrt{30}}{-4}
=-\frac{2\sqrt{30}}{-4}
=-\frac{\sqrt{30}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{30}}{2*-2}=\frac{0+2\sqrt{30}}{-4}
=\frac{2\sqrt{30}}{-4}
=\frac{\sqrt{30}}{-2}
$